limit('integrate(t,t,0,x)/x,x,inf);
Is 'limit('integrate(t,t,0,x),x,inf) positive, negative, or zero? pos;
=> 0
Of course the correct answer is INF, since
integrate(t,t,0,x)/x == x/2
More complicated examples (correct answer is INF)
limit(integrate(t/log(t),t,2,a)/a,a,inf) => 0
limit(integrate(t/log(t),t,x,2*x)/x,x,inf) => 0
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Maybe you should try your 1st example without "'" before "integrate":
limit(integrate(t,t,0,x)/x,x,inf); gives the correct answer!
And for your ´more complicated´ examples:
What other answers do you expect, when Maxima isn´t able to solve the
definite integrals???
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Originator: YES
Re the anonymous comments:
> Maybe you should try your 1st example without "'" before "integrate":
> limit(integrate(t,t,0,x)/x,x,inf); gives the correct answer!
Well, of course it does; Maxima can calculate a closed form for that integral. I was using that as a *simple* example of a noun-form integral where limit gives the wrong answer.
> And for your ´more complicated´ examples:
> What other answers do you expect, when Maxima isn´t able to solve the
> definite integrals???
First of all, I expect not to get an *incorrect* answer, 0. If Maxima can't calculate the correct answer, it should return a noun form.
Secondly, in many cases it is possible to calculate the limit without being able to calculate a closed-form integral. For example,
limit( integrate( exp(t)/t, t, 1, x) , x, inf) = inf
(I'm surprised that integrate(exp(t)/t,t,1,inf)
doesn't report it's divergent, but it doesn't...)
limit( integrate( t^5/(t^7+log(t)), x, x+1), x, inf) = 0
etc.
It turns out that limit doesn't have any special code for integrals like this, but it certainly *could*.
Fixed in limit.lisp rev 1.80.
(%i2) limit('integrate(t,t,0,x)/x,x,inf);
(%o2) 'limit(('integrate(t,t,0,x))/x,x,inf)
(%i3) limit(integrate(t/log(t),t,2,a)/a,a,inf);
Is a-2 positive, negative, or zero?
p;
(%o3) inf
(%i4) limit(integrate(t/log(t),t,x,2*x)/x,x,inf);
Is x positive, negative, or zero?
p;
Is 2*x-1 positive, negative, or zero?
p;
Is x-1 positive, negative, or zero?
p;
(%o4) 'limit(gamma_incomplete(0,-2*log(x))/x
-gamma_incomplete(0,-2*log(2*x))/x,x,inf)
Indefinite integral are still buggy:
(%i5) limit('integrate(x,x)/x,x,inf);
(%o5) 0
Maxima now gives a nounformm not zero--I think this is OK and we can close this bug: