Re: [Matplotlib-users] setting user defined color map as default

[Jae-Joon L. <lee...@gm...>]

I don't think there is any user-visible support for registering a
custom colormap.
However, it seems to me that adding the colormap to
matplotlib.cm.datad distionary is enough.
Note that the value need to be a dictionary of RGB specification, not
the actual colormap instance.

for example,

mycolormap = {'blue': ((0.0, 0.40000000000000002, 0.40000000000000002),
          (1.0, 0.40000000000000002, 0.40000000000000002)),
 'green': ((0.0, 0.5, 0.5), (1.0, 1.0, 1.0)),
 'red': ((0.0, 0.0, 0.0), (1.0, 1.0, 1.0))}

matplotlib.cm.datad["mycolormap"] = mycolormap
rcParams["image.cmap"]="mycolormap"

Having a function (like jet in pylab) would not be also difficult.
Take a look at the definition of "jet" function (for example) in the
pylab.py.

We may be better to have a proper way to register a custom colormap.
I'll try to take a more look later, but any patch will be appreciated.

Regards,

-JJ



On Thu, Jul 30, 2009 at 3:48 AM, Philipp
Lies<phi...@go...> wrote:
>
> Does no one have an idea? If not, this is a severe usability bug!
>
> Philipp Lies wrote:
>>
>> Hi,
>>
>> I just created a hsv-like color map with gray levels only, now I'd like to
>> use this as default color map. But how? Calling it like hsv() does not
>> work and I did not find a hint in the documentation how to set a user
>> defined color map interactively as default color map.
>>
>> Cheers
>>
>> Philipp
>>
>
> --
> View this message in context: http://www.nabble.com/setting-user-defined-color-map-as-default-tp24587528p24733739.html
> Sent from the matplotlib - users mailing list archive at Nabble.com.
>
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