RE: [Jython-users] basestring

[Jeff N. <jn...@ac...>]

I can just use:

   isinstance("s", (StringType, UnicodeType))

but it does seem like Jython has a basestring type from which both
StringType
and UnicodeType inherit.  For instance:

Jython 2.2a1 on java1.5.0_06 (JIT: null)
Type "copyright", "credits" or "license" for more information.
>>> s =3D "str"
>>> c =3D s.__class__
>>> c.__bases__
(<type 'basestring'>,)
>>> u =3D u"str"
>>> u.__class__.__bases__
(<type 'basestring'>,)

I was just thinking it would be more compact and faster to check against
basestring but it isn't in the types module or a builtin.  I could add
it
to the types module but that wouldn't be portable to CPython.

Anyway thanks,
Jeff.

> -----Original Message-----
> From: Frank Wierzbicki [mailto:fwi...@gm...]=20
> Sent: Friday, May 26, 2006 6:21 PM
> To: Jeff Norton
> Cc: jyt...@li...
> Subject: Re: [Jython-users] basestring
>=20
> Jython does not have a basestring type, and probably never=20
> will.  It is kind of an implementation detail in CPython --=20
> and will disappear in Python3000 anyway (although the=20
> following probably won't work in Py3000 eithen).  You can get=20
> the some effect by using:
>=20
> >>> from types import StringTypes
> >>> str in StringTypes
> 1
> >>> unicode in StringTypes
> 1
> >>> type("s") in StringTypes
> 1
> >>> type(u"s") in StringTypes
> 1
>=20
>=20
> On 5/26/06, Jeff Norton <jn...@ac...> wrote:
> >
> >
> >
> >
> > I've got a lot of Python 2.3 code that uses the basestring=20
> builtin type.
> > E.g.
> >
> >     if isinstance(obj, basestring):
> >
> > Jython 2.2a1 doesn't seeme to have a basestring builtin.=20
> Anyone know=20
> > how to get access to it?
> >
> > Thanks,
> >
> > Jeff Norton.
>=20