RE: [Jython-users] how to implement zope page template with java

[Pieter C. <Pieter.Claerhout@Creo.com>]

You might be able to get it working with SimpleTAL.

SimpleTAL is a stand alone Python implementation of the TAL, TALES and =
METAL
specifications used in Zope to power HTML and XML templates.

http://www.owlfish.com/software/simpleTAL/

I gave it a quick go on Jython 2.1 and it looks like it's working fine.

Cheers,


pieter

Creo
pieter claerhout | product support prinergy | tel: +32 2 352 2511 |
pie...@cr... | www.creo.com

IMAGINE CREATE BELIEVE(tm)


-----Original Message-----
From: liu...@ho... [mailto:liu...@ho...]=20
Sent: 31 December 2003 17:39
To: jyt...@li...
Subject: [Jython-users] how to implement zope page template with java


zope page template(zpt) is an excellent protocol for web designers.
it stuck me at first glance,but java is my primary language,so java=20
implemetion of zpt is required.
when I start searching,only javazpt found(javazpt.sourceforge.net).
it's developed too slow and under GPL. I prefer a stable one,...,more =
and=20
more expected.
...but now,I had to start from jython,for zope is open-source,in =
public=20
domain,and ZOPE3 is in CVS already. what i should do is  using jython =
to=20
stick zope's tal,tales,context module with java servlet.
my question is: my jython version is 21,and zope3 like python2.3. if =
jython=20
import zope.pagetemplate.pagetemplate,error occurs.
----------------------------------------------------------

>>> from zope.pagetemplate import pagetemplate as pt
Traceback (innermost last):
  File "<console>", line 1, in ?
  File =
"D:\Python23.3\Lib\site-packages\zope\pagetemplate\pagetemplate.py",=20
line
 23, in ?
  File "D:\Python23.3\Lib\site-packages\zope\tal\talparser.py", line =
18, in=20
?
  File "D:\Python23.3\Lib\site-packages\zope\tal\taldefs.py", line 19, =
in ?
  File "D:\Python23.3\Lib\site-packages\zope\tal\interfaces.py", line =
16,=20
in ?
  File "D:\Python23.3\Lib\site-packages\zope\interface\__init__.py", =
line=20
73, in
 ?
  File "D:\Python23.3\Lib\site-packages\zope\interface\interface.py", =
line=20
269
                            yield interface
                                  ^
SyntaxError: invalid syntax

--------------------------------------------------------

it seems that jython can't support python's new version,
what can I do?
Must I change the design from java--jython--python to java--C--python?

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