RE: [Jython-users] overloading int and boolean

[Stephen T. <ste...@ho...>]

For any Java method whose return type is either the boolean primitive or
the Boolean wrapper class, Jython will coerce the returned value into a
Python integer (as you've observed).  However, the returned value can be
coerced back into a Java boolean with the Boolean wrapper class
constructor, like so:

>>> from java.lang import Boolean
>>> t = TestOverload()
>>> t.get(Boolean(t.getBoolean()))
'BOOLEAN'

Regards,
Stephen

> -----Original Message-----
> From: jyt...@li... 
> [mailto:jyt...@li...] On Behalf 
> Of nicola de candussio
> Sent: Friday, August 01, 2003 8:51 AM
> To: jyt...@li...
> Subject: [Jython-users] overloading int and boolean
> 
> 
> Hello everyone,
> 
> I am sure this very topic has been discussed before but I 
> could not find any 
> reference so here it is:
> 
> I have problems calling overloaded java methods from jython 
> (please note 
> they are java primitive types)
> 
> Example:
> 
> given the following java  class
> 
> public class TestOverload {
> 
>     public String get(boolean p){
>         return "BOOLEAN";
>     }
> 
>     public String get(int p){
>         return "INT";
>     }
> 
>     public boolean getBoolean(){
>         return false;
>     }
> }
> 
> I understand that calling  the get method passing the a 
> jython boolean 
> expression returns "INT" because false or true are mapped to 
> int but I am 
> confused when I execute
> 
> t= TestOverload ()
> t.get(t.getBoolean())
> 
> and I receive "INT"
> 
> Does it mean that the the boolean value of getBoolean is 
> converted to 0 and 
> then passed to get as an int?
> If yes, is there any way to have the (java) expected behavior?
> 
> Thanks in advance
> 
> Nic