[Exist-open] XQuery on Java

[Andrey N. <A.N...@uc...>]

Hello!

1.=20
Are there any ways to quickly update some parts of resource?
Suppose, I have to change some attribute in some tags, so I wrote SAX =
filter and used setContentAsSAX/getContentAsSAX on my resource and then =
storeResource.
It works, but too slow.=20
How to do it faster?=20
2.
If I retrieve some resource AsDOM, then are there any fast ways to walk =
through it using XPath expressions?
And again, how to store it in a fast way?

Andrey Neverov,                               ICQ UIN 225538846
Software Engineer                            +38 (044) 229-3790
UCMG, IT dept.                                http://www.ucmg.com.ua