Re: [amfphp] Returning Custom Objects

[Klaasjan T. <k.t...@mi...>]

Have a look at the slightly outdated (but soon to be updated) tutorial on
actionscript.org:

http://www.actionscript.org/tutorials/intermediate/PHP_Remoting/index.shtml

A snippet from this page:

test = new Object();
test.foo = "bar";
talkback.returnArray(test);

and on the PHP side:

function returnArray ($in) {
                  $objVal = $in['foo'];
                  return array("result"=>"Your Object contained the value
$objVal");
}

So yes, you can create custom AS objects and use them in PHP

Klaasjan



----- Original Message -----
From: "myweb onokazu" <on...@my...>
To: <amf...@li...>
Sent: Friday, March 28, 2003 11:09 PM
Subject: Re: [amfphp] Returning Custom Objects


> How about passing a custom object as a parameter?
>
> for example, I have a function in PHP that expects my custom object as a
> parameter:
>
> function myFunc(&$myObject){
>  // do something with $myObject object and return something
> }
>
> Is it possible to use this function from within the fla files?
>
>
>
> ----- Original Message -----
> From: Dv8
> To: amf...@li...
> Sent: Saturday, March 29, 2003 5:37 AM
> Subject: Re: [amfphp] Returning Custom Objects
>
>
> Sweet, man! Thanks :)
> ----- Original Message -----
> From: Klaasjan Tukker
> To: amf...@li...
> Sent: Friday, March 28, 2003 2:14 PM
> Subject: Re: [amfphp] Returning Custom Objects
>
>
> Construct an array before returning it?
>
>     $result = array();
>     $result["insid"] = $insid;
>     $result["name"] = $name;
>     $result["max"] = $max;
>     return $result;
>
> Klaasjan
> ----- Original Message -----
> From: Dv8
> To: amf...@li...
> Sent: Friday, March 28, 2003 8:40 PM
> Subject: [amfphp] Returning Custom Objects
>
>
> Is there any way to return custom objects?
>
> [example]
> if (!$userid) {
>      mysql_query("INSERT INTO users (lastseen, username) VALUES
> ($time,'$name')");
>      $insid = mysql_insert_id();
>      mysql_query("INSERT INTO messages (msgtime, userlink, message) VALUES
> ($time,1,'[JOIN]$name')");
>
>      $max = mysql_result(mysql_query("SELECT max(msgid) FROM
messages"),0) -
> 15;
>      return "$insid, $name, $max";
> }
> [/example]
>
> Instead of returning a String can I return and Array? Or an Object?
>
>
>
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