Totya

Thanks for the answer! :) I found the "String name" option, I don't know why I didn't see it at first. In "Simple expression" mode, it still didn't find the partial string, then I realized the problem was that it doesn't recognize the * symbol. So it's searching for a partial string by default, which is annoying, it could accept * as well. It doesn't show anywhere in the search window that it's searching for a partial string by default, if it were written there, I wouldn't have to write to the forum...

Hello! In 2.59 I can't find such an option (Find) as "String Name" (I read this on the forum a while ago) There is a method in the help that partially works, for example I have an "Email" stringfield, and it finds them (xpath search): //Entry/String[(Key = 'Email')] However, no matter what I do, I can't use a wildcard, how is that possible: "*Email*" Thank you!

Hello! In 2.59 I can't find such an option (Find) as "String Name" (I read this on the forum a while ago) There is a method in the help that partially works, for example I have an "Email" stringfield, and it finds them (xpath search): //Entry/String[(Key = 'Email')] However, no matter what I do, I can't use a wildcard, how is that possible? "Email"? Thank you!

Nice, I read manuals and I try it. I'm about beginner in sql. Query designer its a good idea, but slightly compicated to use it, because my simple query (SELECT-FROM-WHERE(AND, OR)) from the syntax page, in the designer page changed to many INNER JOIN, and its hard to hard to grasp for me. But I think its my problem. Thanks for this tool! :)

Okay, Its done via http://kenfallon.com/adding-sqlite-as-a-datasource-to-sqleo/ pls. delete this topik.

Okay, Its done via https://sqleo.sourceforge.io/guide/English_SQLeo_Help.htm#_Toc467091854 pls. delete this topik.

Okay, Its done via [docs]https://sqleo.sourceforge.io/guide/English_SQLeo_Help.htm#_Toc467091854) pls. delete this topik.

Hi! How can I use this software with sqlite databese to build query? Hogy can I open sqlite database? Thanks!