Re: [wxlua-users] wxlua watch expression doesn't work

[Milind G. <mil...@gm...>]

Thanks for the update,

Milind

On Thu, May 17, 2012 at 1:55 PM, John Labenski <jla...@gm...> wrote:

> On Thu, Jan 5, 2012 at 6:36 PM, Milind Gupta <mil...@gm...>
> wrote:
> > Hi,
> >      Posting the message again to find out if it is possible to watch
> value
> > of keys inside a table. When I tried that the watch just gives an error
> > message saying:    "string:Lua:Syntax error during pre-compilation" ?
> >      Just a question, does everybody just use the debug library to debug
> > their code in Lua or is there a good graphical debugger that can help. I
> > tried Lua Eclipse, it didn't work for me, cannot make Scite work to
> debug in
> > Linux but even in windows its debugging is more command line rather than
> > graphical. WxLua seemed to be the only solution that was working good but
> > then I encountered this problem?
>
> Sorry about the delay... Yes there is a problem, but also a temporary
> fix. Unfortunately the remote debugger expression evaluator does
> double duty, a) run code like "a = 1+2" to set a varible in the
> debugger Lua state or to get variable values. So, when it finds a '.'
> it thinks there is an expression to evaluate not a variable.
>
> The solution, put a watch on these two things:
> "a = MyTable.Key" : should say Ok on the value side
> "a" : should be the value of MyTable.Key
>
> I just have to find the time to separate the functionality of the two
> things so they both work.
>
> Regards,
>    John
>
>
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