Re: [Wrapper-user] Help regarding starting a service

[Sujatha B. <suj...@td...>]

Hi,
=20
I tried that..but still the java is not returning and the wrapper is givin =
a message saying=20
that unable to start the service after trying 5 times.
=20
How do i handle this? Is this something to be fixed with wrapper or with th=
e java?
My program will be running as a background thread..and is not suppose to re=
turn until you execute stop on the service.
=20
Please guide me
=20
Thanks
Sujie=20
=20
----- Original Message -----
From: wra...@li... on behalf of Rodrigo Vega=
=20
Sent: Wed, 5/9/2007 18:17
To: wra...@li...
Subject: Re: [Wrapper-user] Help regarding starting a service=20
=20
=20
I think your are making a main method, and this method call a thread. If th=
is
is your case you must do something like


public static void main(String args[]){
      YourThread t =3D new YoruThread();
      t.start();
      t.join();
}



In that way your java program will not day until the thread die.




Rodrigo G. Vega
i411 Argentina
rv...@i4...

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-----Original Message-----
From: wra...@li... on behalf of Sujatha
Bharathan
Sent: Wed 05/09/2007 12:28
To: wra...@li...
Subject: [Wrapper-user] Help regarding starting a service

Hi,

I have used the wrapper class to create a windows service . I am successful
in creating the service but have an issue in starting it.

My service calls a java and the java starts a thread to run and it does not
return anything and has to keep running in the background.

But when i click on start in administrative tools>> service>> my service  i=
t
comes back and says unable to start and it failed.
My java program is a thread and it will not return anything , Is there any
configuration variable which i could specify in my conf file so that i coul=
d
just run the java program
and return immediately without waiting for an output?

Looking forward for your help.

Thanks in advance.
Sujie