Re: [Wrapper-user] Using WrapperSimpleApp Integration

[Leif M. <le...@ta...>]

David,
If that is what your command line looks like then your CLASSPATH must be 
getting
defined as a system property. I assume that you are having problems when 
running as
a service? This would be because you have not set the CLASSPATH as a 
system wide
environment variable.

That said, the CLASSPATH environment variable is BAD BAD BAD! You will
run into problems if you try to use more than one application on the 
same machine.

You really should be using the -classpath parameter to the JVM. This is the
normal way to be using the wrapper.

Make you you have defined classpath properties for each jar and classes 
directory
that would normally go on your classpath.

If you have more questions, include your wrapper.conf file so I can see 
exactly
what you are doing.

Cheers,
Leif

David Schulberg wrote:
>
> A simple question regarding using the Method 1 - WrapperSimpleApp 
> Integration with my java application which I normally run from Windows 
> command line
>
> “java proxy parm1 parm2 parm3”.
>
> Getting error: Unable to locate the class proxy: 
> java.lang.ClassNotFoundException: proxy
>
> What should I be defining in my wrapper.conf to overcome this error? 
> The application proxy comprises just class proxy with method
>
> ‘public static void main(String args[]).’
>
> Regards,
>
> David
>