RE: [Wrapper-user] Running Java's rmiregistry as a service

[Alex V. <ale...@ap...>]

Gerardo,

Here is an (untested) idea: Have your wrapper listener create and export =
an
RMI registry fromm within the JVM:

    public Integer start(String[] args)
    {
        try
        {
            java.rmi.LocateRegistry.createRegistry(4500)
        }
        catch (Throwable t)
        {
            t.printStacktrace();
            Return new Integer(1);
        }
 =20
        System.out.println("Registry started on port 4500");
        return null;
    }
}

Rgrds, Alex.

PS: If it works, I'd be interested to know about it.

_______________________

Alexandre Vauthey
Director of Server Technology
Application Networks
444, Ramona Street
Palo Alto, CA 94301
Tel: 1 (650) 462-7224

www.application-networks.com
_______________________
-----Original Message-----
From: wra...@li...
[mailto:wra...@li...] On Behalf Of Gerardo =
Rojas
Sent: Tuesday, February 17, 2004 11:07 AM
To: wra...@li...
Subject: [Wrapper-user] Running Java's rmiregistry as a service


All,=20
I have been trying unsuccesfully to run Java's builting "rmiregistry" as =
a
service.  I have tried several diff combinations but nothing seems to =
work.
I have downloaded the Wrapper and made all changes.  I believe this is =
not
working because the rmiregistry is an executable.  Any feedback or HELP
would be appreciated.


--=20
Gerardo S. Rojas=20
mailto: gr...@st...=20