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From: Nalli, S. <san...@hp...> - 2014-05-30 01:24:20
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Hi, So I start UML with the cmdline ./linux rootfstype=hostfs rw mem=1G init=/bin/bash When the bash shell comes up, I run my prog : ./my_prog 6173 pts/8 00:00:00 linux 6180 pts/8 00:00:00 linux 6181 pts/8 00:00:00 linux 6182 pts/8 00:00:00 linux 6183 pts/8 00:00:00 linux 6188 pts/8 00:00:13 linux The last item in the list with PID is 6188 is my program. I can tell because my_prog increments a counter in an infinite loop And consumes CPU cycles. It shows up on "top" as the dominant process. My question: 1. /proc/6188/exe is invalid. Why ?? I mean, it doesn't point to anything. Shouldn't it point to my_prog or something ? 2. What do the 4 UML processes 6173, 6180, 6181, 6182 do ? (6183 is /bin/bash whos "exe" symlink is also doesn't point to anything !!) 3. When a UML process, say my_prog (PID 6188) makes a system call, where is the system call executed - is it within the addr space of 6173 (the UML kernel process) or 6188 (my_prog running in UML ??) -Sanketh |