From: <pf...@cs...> - 2005-07-07 15:44:38
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>> >> If you didn't mean to overload T, then if this happens >> time T1: agent receives sensations >> time T1 + N1: (N1 is the thinking time) agent sends request time notify >> for time T2 (where T2 > T1 + N1) >> time T2: agent receives time notify, spends N2 time thinking and sends >> action A >> time T2 + N2 + L: (L is the server's action latency) action A is >> actualized >> > > If N2>N1, then it is possible that T1+N1+L == T2+N2+L. How does the > server realize the actions in this case? You can get this condition, but not how you say. The correct condition in my original mail is T2 >= T1 + N1. If T@ = T1+N1 and N2 = 0, then T1+N1+L=T2+N2+L. In this case, SPADES provides no guaruntees about about ordering, but maybe the soccer simulation does. Maybe you want to file a feature request for SPADES to provide an ordering guaruntee here? -- Pat Riley |