Re: [Springframework-developer] Bug?

[<jue...@we...>]

Sorry, step back: This is actually intended behavior. If you don't =
specify an index, the constructor argument value is considered generic, =
to be matched any number of times. So in your case, simply add index =
attributes:

  <bean
    id=3D"personType"
    class=3D"com.marathon.util.sdo.DefaultType">

    <constructor-arg index=3D"0"><ref =
bean=3D"entityType"/></constructor-arg>
    <constructor-arg =
index=3D"1"><value>m:Person</value></constructor-arg>

Juergen


-----Original Message-----
From: spr...@li...
[mailto:spr...@li...]On Behalf
Of j=FCrgen h=F6ller [werk3AT]
Sent: Wednesday, June 02, 2004 6:40 PM
To: spr...@li...
Subject: Re: [Springframework-developer] Bug?


Indeed, that's a bug! I've just fixed it; will be part of 1.0.2.

Juergen


-----Original Message-----
From: spr...@li...
[mailto:spr...@li...]On Behalf
Of Andy Depue
Sent: Wednesday, June 02, 2004 6:17 PM
To: spr...@li...
Subject: [Springframework-developer] Bug?


I think I'm seeing a bug in Spring, but thought I'd bounce it off others =

first.  I have a class with multiple constructors, two of which are =
defined=20
as follows:
  public DefaultType(Type superType, String qualifiedName)
and:
  public DefaultType(Type superType, String uri, String name)

I use the following XML to configure:

  <bean
    id=3D"personType"
    class=3D"com.marathon.util.sdo.DefaultType">

    <constructor-arg><ref bean=3D"entityType"/></constructor-arg>
    <constructor-arg><value>m:Person</value></constructor-arg>
    <property name=3D"typeProperties">
      <list>
        ...
      </list>
    </property>
  </bean>

Spring will call the second constructor instead of the first, passing in =

"m:Person" to both String parameters, equivalent to this:
  new DefaultType(entityType, "m:Person", "m:Person")

Am I doing something wrong, or is this a bug?  This is with Spring 1.0.1 =

(release)


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