Re: [Simpleweb-Support] Problem decoding "+" characters (%2B)

[Niall G. <gal...@ya...>]

Hi,=0A=0AThis seems quite strange, I am sure I have tested this case many t=
imes. I have also taken a look at the URIParser and it does not decode the =
query, it simple spots the '?' and hands it off to the ParameterParser, whi=
ch then decodes it. What exactly are you doing to create this scenario? Are=
 you simply performing a Request.getParameter(name) from a POST or GET?=0A=
=0ANiall=0A=0A----- Original Message ----=0AFrom: "Wilson, Terry" <TXWilson=
@ea.com>=0ATo: sim...@li...=0ASent: Friday, May =
11, 2007 1:18:30 AM=0ASubject: [Simpleweb-Support] Problem decoding "+" cha=
racters (%2B)=0A=0A=0A=0A=0A =0A =0A=0A<!--=0A _filtered {font-family:Wingd=
ings;panose-1:5 0 0 0 0 0 0 0 0 0;}=0A/* Style Definitions */=0A p.MsoNorma=
l, li.MsoNormal, div.MsoNormal=0A=09{margin:0in;margin-bottom:.0001pt;font-=
size:12.0pt;font-family:"Times New Roman";}=0Aa:link, span.MsoHyperlink=0A=
=09{color:blue;text-decoration:underline;}=0Aa:visited, span.MsoHyperlinkFo=
llowed=0A=09{color:purple;text-decoration:underline;}=0Aspan.EmailStyle17=
=0A=09{font-family:Arial;color:windowtext;}=0A _filtered {margin:1.0in 1.25=
in 1.0in 1.25in;}=0Adiv.Section1=0A=09{}=0A-->=0A=0A=0A=0A=0A=0A=0AHello,=
=0A =0A=0A  =0A =0A=0AI=92m having trouble sending the plus (+) character f=
rom=0Aa client to a simple (3.1.3) server. I=92m hoping someone could point=
 out=0Awhat I=92m doing wrong J=0A =0A=0A  =0A =0A=0AMy understanding is th=
at the plus character needs to be=0Apercent encoded by the client to this: =
%2B=0A =0A=0A  =0A =0A=0ASo let=92s take this URL: http://server?val=3D%2B=
=0A =0A=0A  =0A =0A=0AWhen I send that to the server and print out the Para=
meters=0Aobject I get from the request I see this:=0A =0A=0A  =0A =0A=0Aval=
=3D+=0A =0A=0A  =0A =0A=0ALooks good so far, %2B has been decoded into a =
=93+=94=0Acharacter. When I try to get the value with parameters.getParamet=
er(=93val=94),=0Awhat I get back is a space (=93 =93). The javadoc for Para=
meterParser mentions=0Athat the =93+=94 character is replaced with a space,=
 so I know this is=0Adone intentionally. Looks like the URL is first decode=
d into the parameters=0Aobject and then this special rule is applied when r=
etrieving individual=0Aparameter values.=0A =0A=0A  =0A =0A=0ABut what if I=
 actually need to get a plus character through?=0AI thought that the =93+=
=94 character is just shorthand for the space=0Aencoding of %20. Why is thi=
s plus character rule being applied after the=0Adecoding has already taken =
place?=0A =0A=0A  =0A =0A=0AI might just be confused and this works exactly=
 as it should=0AJ If that is the case how is a client=0Asupposed to pass in=
 a plus character value? I=92ve tried various ways of=0Aencoding, but I hav=
en=92t been able to get a plus sign to appear in the=0Astring I get from th=
e getParameter(string) call.=0A =0A=0A  =0A =0A=0A  =0A =0A=0AThanks and an=
y help appreciated,=0A =0A=0A  =0A =0A=0ATerry=0A =0A=0A  =0A =0A=0A  =0A =
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