7zip extract to folder like archive name

[Pilligrim]

I use command line version of 7zip - 7za.exe. Pls tell me how can I extract archive in to folder like the name of archive file. For example:

extract archive 02.10.2007boss.7z to /02.10.2007boss/file.txt

[SeldomGood]

The manual is your best friend.

Check the "-o" switch.

To Igor Pavlov: it may be worth pointing out in the manual page for "-o", that using it with wildcard works, maybe with a simple example like:

7z x archive.zip -o*

Regards

[Pilligrim]

You are right! Wonderfull Switch :). I would tell magic switch! But from a management it is not obvious :).

[quote]
-o (set Output directory) switch
Specifies a destination directory where files are to be extracted.

This switch can be used only with extraction commands.

Syntax
-o{dir_path}

{dir_path}
This is the destination directory path. It's not required to end with a backslash.
Example
7z x archive.zip -oc:\Doc

extracts all files from the archive.zip archive to the c:\Doc directory.
[quote]

Many thanks for the help!

[kabsdk68712]

hey seldom god, i couldnt get the wildcard to work with -o. It threw following error when run into a folder with no subfolders.

Command Line Error:
Unsupported command:

Is it normal wildcard and requires a folder to be there? I thought that it would automatically apply the package name to folder.

[Ferneu]

Just tried it using archives with folders and archives without folders. Both worked.

By the way, thank you very much SeldomGood. Had no idea -o* was a thing. And it even supports inserting a couple of sub directories in there too, like -oa/b/c/d/*