[sdcc-devel] [ sdcc-Feature Requests-860006 ] 8x8 multiply uses 16bit intermediate

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Feature Requests item #860006, was opened at 2003-12-14 21:57
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Category: None
Group: None
Status: Open
Priority: 5
Submitted By: Frieder Ferlemann (frief)
Assigned to: Nobody/Anonymous (nobody)
Summary: 8x8 multiply uses 16bit intermediate

Initial Comment:
the other operators are fine, but multiply 
uses a 16bit intermediate: 
 
volatile unsigned char s,t; 
void main() 
{ 
  s=t*5;    // this uses an 16 bit intermediate 
  s=t/5;    // whereas the other operators are fine 
without 
  s=t%5; 
  s=t+5; 
  s=t-5; 
} 
 

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