#677 "Integer overflow in expression"

[Mika Rasimus]

typedef unsigned long LONG;

void main(void)
{
LONG apu=24*60*60;
}

"warning: integer overflow in expression"

It's a little thing but still a very annoying and
unnecessary feature...

SDCC :
mcs51/gbz80/z80/avr/ds390/pic16/pic14/TININative/xa51
/ds400/hc08 2.3.7 (Jan 11 2004) (MINGW32)

[Erik Petrich]

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You would rather not know that apu is initialized with 20864
rather than 86400?

An int multiplied by an int is also an int, regardless of
whatever it may be assigned to. The assignment will cast the
resultant int to a long, but overflow has already occured.
If you want the multiplication to be computed with a long
result, at least one of operands should be long. For example:

LONG apu = 24*60*60UL;
or
LONG apu = 24*60*(LONG)60;

[Bernhard Held]

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You'd better be happy about this warning instead of complaining
about it!

[Mika Rasimus]

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Oops... My mistake... again... I didn't think it works that way.
With my previous compiler I have managed to avoid the
problem just with a blind luck :)

Ok... I don't think it is annoying behaviour at all... Unlike that
ANSI-C-thing of expanding an explicitly defined unsigned char
to a signed int. There must be a good reason for that but I
can't figure it out =P

Any way... No matter how much I complain about ANSI-
features that I have never heard of, you still keep up good
work :)