From: Luigi B. <bal...@ma...> - 2002-06-29 11:40:22
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At 01:29 PM 6/27/02 +0200, Ferdinando Ametrano wrote: >Not quite the same thing indeed. I might be wrong but your formula is >quite similar to "geometric interpolation" > dfx = (df1^((t2-tx)/(t2-t1)))*(df2^((tx-t1)/(t2-t1))). Which is exactly the same as your loglinear formula. Playing the devil's advocate and loving it, Luigi |