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From: Andre L. <An...@de...> - 2002-06-26 11:33:46
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Nando, I just checked out loglinearinterpolation and noted the change you implemented. I have a comment. Correct me if i'm wrong, but I see you are using linear interpolation on cont. compounded rates to get to the resulting discount factor i.o.w: cf1 = ln(df1), cf2 = ln(df2) dfx = exp(cf1+((tx-t1)/(t2-t1))*(cf2-cf1))) I implemented loglinear interpolation to get to the result i.o.w: dfx = (df1^(tx/t1*(t2-tx)/(t2-t1)))*(df2^(tx/t2*(tx-t1)/(t2-t1))) Not quite the same thing. If that is your institution's standard, fine, but could I then rename your implementation as contcomplinearinterpolation.hpp (or some such name), as I see the original implementation being log-linear interpolation? We could the implement a mechanism in DiscountCurve to distinguish which to use? I had a problem with the original implementation between t1 = 0 and some tx which I solved by testing for this condition and calculating dfx: dfx = 1/1+((1/df2-1)/t2)*tx Comments? Andre ------------------------------------------------------------------------- This e-mail is intended only for the use of the individual or entity named above and may contain information that is confidential and privileged, proprietary to the company and protected by law. If you are not the intended recipient, you are hereby notified that any dissemination, distribution or copying of this e-mail is strictly prohibited. Opinions, conclusions and other information in this message that do not relate to the official business of our company shall be understood as neither given nor endorsed by it. |