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From: Kakhkhor A. <kab...@gm...> - 2010-09-15 20:33:03
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denom and num aren't continues. Looks like "if (!denom)" was meant to deal with the case when denom is exactly zero because of particular choice of i, alpha and beta. In that case num must be exactly zero too. For example, if i=0, alpha=0 and beta=0, then denom is bitwise 0. In that case num must be bitwise zero too. It will work if the test "if (!denom)" is meant to be true only for a particular values of i, alpha and beta. |