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[Asaf S. <as...@as...>]

Hello,

I have some directory that looks like this:



Dc=3Daup

Ou=3Dcustomers

Ou=3DCustomer's name

=20

I just want to get a list of the customer's name,

There's anyway to do it? since search_s returns the entire line with the
whole DNS.

=20

My code look like this:

=20

import ldap

conn =3D ldap.initialize("ldap://ldap_server")

conn.set_option(ldap.VERSION, ldap.VERSION3)

conn.simple_bind_s(ADMIN_USER)

=20

dn=3D"ou=3DCustomers,dc=3Dalwaysup"

res =3D conn.search_s(dn, ldap.SCOPE_ONELEVEL, "objectClass=3D*", [])

=20

for name,attrs in res:

  print name

=20

ofcourse it prints the whole path, output is something like that:



ou=3DCustomerName,ou=3DCustomers,dc=3Daup

=20

I just want to get a list of 'CustomerName', even without the OU.

=20

Well, I guess this is a python question, not an python-ldap one but
maybe there are some functions that make it easy to retrieve only
specific part of the result in python-ldap?



Thanks.