Re: [Pysaprfc-users] RFC Server Module

[Klavdij V. <von...@si...>]

You have to register the module with r/3 using transaction sm59. Please, check 
SAP help but basically there are two options - starting program from either 
backend or frontend (or registered server machine via rsh), or registernig 
already running process. If you go for second option you have to pass certain 
arguments when starting program, usually those are -a<prog_name> -g<gateway> 
-x<gw_port> where prog_name is program id from sm59, gateway is a name or ip 
of sap gateway server and gw_port is the port gateway is runing on. When 
using first option and running on Windows you have to produce an .exe using 
py2exe or similar tool, on Unix/Linux making script executable using chmod is 
enough.

HTH,
Klavdij

> The following Module should run out of the box. But it says "exception
> 'connection failed'". I have o clue whats going on. Can pls somebody give
> me a hint how the module has to be started
>
> #!/usr/bin/env python
> # -*- coding: latin_1 -*-
>
> import pysap
> class MyFunc(pysap.RFC_SERV_FUNC):
>     _name_='Z_MY_FUNC'
>     _importing_=[('IN_VALUE','I')]
>     _exporting_=[('OUT_VALUE','I')]
>
>     def run(self,handle):
>         self['OUT_VALUE']=2*self['IN_VALUE']
>
> import sys
> srv=pysap.RfcServerEx()
> try:
>     srv.register_func(MyFunc)
>     srv.main_loop(sys.argv)
> except pysap.SapRfcError, msg:
>
>     print "exception %s " % (msg)
>
>     sys.exit(1)
>
>
>
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