#57 Char constants (literals like 'a') are of type long, not int

I stumbled upon the following problem:

#define sprintf StrPrintF

A code like this:
sprintf(x, "%c", intval ? '1' : '0'); DOESN'T WORK,

while

sprintf(x, "%c", (int)(intval ? '1' : '0')); WORKS.

(where x is an initialized char*)

StrPrintF declaration is seen by the compiler before
it is used, so this behaviour is incorrect. '1' and
'0' must be automatically converted to int.

[John Marshall]

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True. For now, put the cast in. This is on the list for
fixing when we update to GCC 3.x, but I don't want to do it
twice, which is what would happen if we did it now. See
also
http://www.escribe.com/computing/pcpqa/m18245.html