Re: PHP Weather 2.1.2
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From: Dan M. <da...@da...> - 2003-05-12 16:58:14
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I have figured out after struggling a bit how to pull most of the information in 2.1.2, but I am still having difficulties pulling "Clouds" and "Weather." I know that the information is in an array, but I am unclear on how to bring it out of the array. I also cannot seem to pull wind direction (SW, NW, W), but I can pull the compass degree (135, 90, 110). Here is the code: $weather = new phpweather(); $icons = new pw_images($weather); $location = $weather->get_location(); $image = $icons->get_sky_image(); $data = $weather->decode_metar(); $temp = $data[temperature]; $windvar = $data[wind]; <-----This Doesn't Work $cloudvar = $data[clouds]; <-----This Doesn't Work $time = date("m/d/y g:i a",($data[time])); $weathervar = $data[weather]; echo "\n"; echo "<div align='center'> Portland, Oregon<br /> <img src=\"$image\" height='45' width='75' border='0' alt='Current Sky' />"; echo "<br />$weathervar[condition]<br /> </div>"; echo "<b>Temperature:</b> $temp[temp_f]°F<br />"; echo "<b>Humidity:</b> $data[rel_humidity]%<br />"; echo "<b>Wind:</b> $windvar[miles_per_hour]mph<br /> <div align='center'>$time</div> "; Thank you, Dan Martin |