Re: [Php-java-bridge-users] Java 1.5 varargs, NoSuchMethodException

[<php...@li...>]

I think you could/should use an array(). For example the code below displays 12:

--- varargs.php ---

<?php require_once("http://localhost:9092/JavaBridge/java/Java.inc");

java_require("varargs.jar");
$varargs = new java("Varargs");

$t1 = new java('Varargs$Test', 1);
$t2 = new java('Varargs$Test', 2);

echo $varargs->varargs(array($t1, $t2));
?>

--- Varargs.java ---


public class Varargs {
    public static class Test {
 public int i;
 public Test (int i) {
     this.i = i;
 }
 public String toString() {
     return String.valueOf(i);
 }
    }
    public static String varargs(Test ...tests) {
 StringBuffer buf = new StringBuffer();
 for (Test test : tests) {
     buf.append(test);
        }
 return buf.toString();
    }
    public static void main(String[] args) {
 System.out.println(varargs(new Test(1), new Test(2)));
    }
}

Peter


       
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