Re: [Php-java-bridge-users] coerce sub-array as Java array

[<php...@li...>]

I tried that, but it doesn't work.  $array will wind up as a php array with
$count elements:

// trying to create 3-element String[] in PHP4
$Array = new JavaClass("java.lang.reflect.Array");
$String = new JavaClass("java.lang.String");
$javaArr = $Array->newInstance($String, 3);
var_dump($javaArr);

Output:

array(3) {
  [0]=>
  NULL
  [1]=>
  NULL
  [2]=>
  NULL
}

Michael.

> -----Original Message-----
> From: php...@li... [mailto:php-
> jav...@li...] On Behalf Of php-java-
> bri...@li...
> Sent: Wednesday, August 15, 2007 5:00 AM
> To: php...@li...
> Subject: Re: [Php-java-bridge-users] coerce sub-array as Java array
> 
> Why don't you create a string array explicitly, for example by using
> java.reflect.Array?
> 
> The code would look like this:
> 
>   $array = java("java.reflect.Array")-
> >newInstance(java("java.lang.String"), $count);
> 
> Please see the documentation for details: http://php-java-
> bridge.sourceforge.net/pjb/extension_mappings.php
> 
> 
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