Re: [Php-java-bridge-users] CXF webservice with PHP: Couldn't execute method java_InternalException

[<php...@li...>]

Thanks for the answer.

IMHI, the manual about java_closure() is not always obvious.

ex:

   1.  function toString() {return "helloWorld";};
   2.  $object =
java_closure<http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure>
   ();
   3.  echo "Java says that PHP says: $object\n";

In this example, no arguments are passed in the java_closure() function.
What does java_closure() transform? Only the last object? It is not clear in
the manual.

ex:

   1.  function hello() {return "hello";};
   2.  echo (string)java_closure<http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure>
   (null, "hello");

In this example, I think the function hello() is transformed, because
"hello" is the second argument. It is a good idea, to change the first line
in ... return "helloWorld";}; to prevent confusion with the second argument
of java_closure() (PHP developpers are KISS-thinkers :-)). The manual talks
about a keymap: maybe give an example? Why is the first argument null?

Now, for my case.

What is $input?

In PHP two classes are declared:
class encodeRequest {
    /**
     * @var string
     */
    public $applicationName;
    /**
     * @var array[1, unbounded] of (object)OriginalDataType
     */
    public $originalData;
}

class OriginalDataType {
    /**
     * @var string
     */
    public $id;
    /**&;
     * @var boolean
     */
    public $randomize;
    /**
     * @var string
     */
    public $inputData;
}

$data = new OriginalDataType();
$data->id = 1;
$data->randomize= false;
$data->inputData = "blabla";

$input = new encodeRequest();
$input->applicationName = "WWM";
$input->originalData = $data;

So $input is an instance of the encodeRequest class. I want this PHP
instance be transformed in a Java instance.

I thought that $java_input = java_closure($input); would do the trick?

Sincerely,

Koen


2011/2/24 <php...@li...>

> Hi,
>
> > 1. I don't understand the remark:
> > "Your java object backed by a php
> > instance doesn't have any public methods."
>
> It's a java.lang.Object which implements no interfaces. Not very
> useful unless your library detects that it is a proxy and directly
> calls its invocation handler. Please see the java_closure() API for
> details at
> http://php-java-bridge.sourceforge.net/pjb/docs/php-api/java/_JavaProxy.inc.html#functionjava_closure
>
> > public static Object[] encode(Object request) throws RuntimeException,
> > Exception {
> >
> > -> I added static: that was logic
> > -> I added RuntimeException, like in the FAQ.
>
> In this case your code will work and I have no explanation for this
> issue either.
>
> But if your library is smart enough to call $java_input's invocation
> handler, please have a look at your PHP code called from the
> invocation handler. It probably calls a library method which throws an
> unchecked exception.
>
> The problem is simply that an unchecked exception has been returned
> from a Java call but not thrown. (You can get around this by setting
> JAVA_PREFER_VALUES, but I think you know that).
>
>
> Be it as it may, if you only want to add a sec header to your soap
> request, you can do this in PHP as well. Or implement it in Java and
> call the entire method from PHP.
>
>
> Regards,
> Jost Bökemeier
>
>
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-- 
*Koen Thomeer*, MD, MSc
http://koen.thomeer.be