Re: [Php-java-bridge-users] How to wrap two PHP objects as java closures, and in Java call a method on the first closure with the second closure as parameter?

[<php...@li...>]

Hi Juergen,

> 	public void call(Object $cca, Object $ccb) {
> 			cca.invoke( $cca, "invokeA", new Object[]{ ccb

> So, the PhpProcedure passed to invokeA() is a new one.

yes, obviously. ccb != $ccb. However, why is this a problem?


> (which in turn causes invokeB() to fail...)
> Did I find a bug here?

What do you mean with causes invokeB() to fail? The test case I've attached in my previous mail runs correctly, invokeB() correctly returned the string ::B, so I don't see the problem.


Regards,
Jost Boekemeier