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From: <php...@li...> - 2008-03-13 09:21:21
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Hi,
> $d2rqF=$session->get("d2rq");
> if(!$d2rqF)
the !$varName works only for PHP values. Please see your PHP documentation for details.
According to the PHP documentation you should use is_null().
Note that is_null() cannot test whether or not the containing object is the Java NULL object or
not. You must convert the Java object into a PHP value first, for example with java_values() or
with a (string) cast.
Regards,
Jost Boekemeier
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