Re: [Php-java-bridge-users] How to get an instance of a running object ?

[<php...@li...>]

Hi,

>     public static void main(String[] args) {
>         obj = new Integer(15);
>         System.out.println(getObj());
>         while(true);
>     }
>     public static int getObj() { return obj; }
> }

Okay. But you may want to use Thread.sleep() instead of the while(true); loop. :)



> I make a jar archive from it (phpjava.jar). The jar contains:
> Main-Class: app.Main
> Class-Path: JavaBridge.jar

Okay.

Next you can run a PHP script as follows:

<?php require("http://localhost8091/JavaBridge/java/Java.inc");
$myClass = new java("app.Main");
echo $myClass->getObj();
?>

 
> I put the archive into my deployment directory 'ext'. This directory
> contains:
> - java/Java.inc
> - hello.php
> - JavaBridge.jar
> - phpjava.jar

I don't understand why this is necessary.


> According to the manifest of JavaBridge.jar, I have also put in 'ext' (just
> in case):
> - php-script.jar
> - script-api.jar

No. These are the JSR223 bindings.


> Here is the php script:
> <?php
> require_once("java/Java.inc");
> java_require("phpjava.jar");
> $myClass = new java("app.Main");
> $obj = $myClass->getObj();
> echo $obj;
> ?>

No. The above script connects to the wrong application (if any). The java_require() is not 
necessary either, your application already knows about app.Main.

 
> I launch the JavaBridge.jar by right-clicking on it and 'execute with

No. You have already started your application.


Regards,
Jost Boekemeier



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