Re: [Php-java-bridge-users] how to debug the php script which calls the java function

[<php...@li...>]

Hi,

> $obj = new Java("parser.ParseNode);
> echo $pobj->printHello();  //printHello is a static

should print something to the debug log.

> //printTest is not a static function 

If the method printTest cannot be called, it means that the defining class is static or it has a
non-public constructor, in which case the PHP/Java Bridge returns the type instead of an instance.
(This behaviour is for compatibility with other bridges, but the recommended way to access a type
is through the java() function, of course.)


Regards,
Jost Boekemeier



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