[Openeeg-list] Alex: Disorder or IRC server.

[Graham S. <ggn...@gm...>]

Thanks for the offer, Alex.

I vote, : "Yes".

Graham


On Thu, 10 Aug 2023, 2:58 pm , <ope...@li...>
wrote:

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>    1. Re: Besselworth calculations (Alexander Houston)
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> ----------------------------------------------------------------------
>
> Message: 1
> Date: Wed, 9 Aug 2023 22:57:53 -0400
> From: Alexander Houston <aho...@gm...>
> To: "Discussion of EEG hardware, software, training protocols, NFB
>         theory - for developers and users."
>         <ope...@li...>
> Subject: Re: [Openeeg-list] Besselworth calculations
> Message-ID:
>         <
> CAE...@ma...>
> Content-Type: text/plain; charset="utf-8"
>
> All,
>
> Would anybody be opposed to creating a discord or IRC server for this
> project? The state of things right now is not friendly for newcomers to the
> project, as most everything is scattered around old wikis, codebases, and
> posts on this mailing list. Many links to the original sourceforge projects
> are only accessible via archival sites like Wayback.
>
> As a newcomer myself, I don't feel it's my place to admin over a server
> like this. However, I'm happy to create one if interest is high but
> familiarity with discord is low.
>
> OpenEEG is a banger hobby concept and it deserves to be accessible in a
> post web 1.0 world ?
>
> Steve: sadly I cannot even begin to comprehend your question, sorry!
>
> Best,
> Alex.
>
> On Wed, Aug 9, 2023 at 10:42?PM Stephen McInturff <
> ste...@gm...> wrote:
>
> > Hello,
> >
> > I'm not sure if this project is still ongoing but I'm going to post and
> > wish for the best.
> >
> > I am attempting to build an Auditory Brainstem Response (ABR) amplifier.
> > The circuit is very much the same as the designs for the "modularEEG"
> > except that the filters are different (I want 300-3kHz while the current
> > designs are mostly <100 Hz). This would mainly involve modifying the
> > "besselworth filter", see screenshot below.
> >
> > My question is how was the cutoff frequency of 59Hz calculated? The
> > equations I've found for this are Fc = 1/(2*pi*sqrt(R232*R288*C234*C231))
> > which equals 152.5 Hz and the gain calculation Gain = (1+R230/R229) =
> 13.19x
> >
> > Could someone help explain how these numbers were calculated in the
> > schematic? I understand that the 3rd pole of this filter is on the
> digital
> > board but how would that play into the calculations?
> >
> > Thank you,
> > Steve Mci
> >
> > [image: image.png]
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