Re: [myhdl-list] Problem converting list of intbv

[Pedro P. <ped...@gm...>]

Guy, thanks for your response.

Unfortunately I can't use tuples because I acually write to the "array" as
well. So allow me to modify my example. Now I have 4 counters and the one
selected with signal s will get incremented and tranfered to the output.

Shouldn't list of intbvs be supported?

from myhdl import Signal, always_comb, intbv, toVerilog

def uint(width, val = 0):
    return intbv(val, 0, 2 ** width)

def u32(val = 0):
    return uint(32, val)

def counters(s, o):
    m = [ u32(0xaaaaaaaa), u32(0xbbbbbbbb), u32(0xcccccccc),
u32(0xdddddddd) ]
    @always_comb
    def logic():
        m[s] += 1
        o.next = m[s]
    return logic

s = Signal(intbv(0)[2:])
o = Signal(intbv(0)[32:])

toVerilog(counters, s, o)

ızznɹpǝԀ oɹpǝԀ


On Tue, Jul 8, 2014 at 5:46 AM, Guy Eschemann <gu...@no...> wrote:

> Hello Pedro,
>
> here's how I would do it:
>
> def mux(s, o):
>     i = (0xaaaaaaaa, 0xbbbbbbbb, 0xcccccccc, 0xdddddddd)
>
>
>     @always_comb
>     def logic():
>         o.next = i[s]
>     return logic
>
> Regards,
> Guy.
>
> On Jul 8, 2014, at 1:16 AM, Pedro Pedruzzi wrote:
>
> Hello,
>
> I am new to this list.
>
> I am getting the following exception while trying to convert a simple mux
> to Verilog.
>
> myhdl.ConversionError: in file list-of-intbv.py, line 12: Not supported:
> list
>
> I know I could use tuple of int (since I am using constants), but I want
> to use lists to implement array of registers and the docs says it is
> possible.
>
> Here is the design:
>
> from myhdl import Signal, always_comb, intbv, toVerilog
>
> def uint(width, val = 0):
>     return intbv(val, 0, 2 ** width)
>
> def u32(val = 0):
>     return uint(32, val)
>
> def mux(s, o):
>     @always_comb
>     def logic():
>         i = [ u32(0xaaaaaaaa), u32(0xbbbbbbbb), u32(0xcccccccc),
> u32(0xdddddddd) ]
>         o.next = i[s]
>     return logic
>
> s = Signal(intbv(0)[2:])
> o = Signal(intbv(0)[32:])
>
> toVerilog(mux, s, o)
>
>
> Any help is appreciated. Thanks.
>
> ızznɹpǝԀ oɹpǝԀ
>
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