Re: [Maxima-discuss] How do I "unquote" 'integrate(cos(y),y) ?

[Eduardo O. <edu...@gm...>]

Perfect! Thanks!!!
Then this generates all the intermediate expressions that I need:

  ex0 : 'integrate((3*cos(2 + sqrt(3*x+4))) / (2*sqrt(3*x+4)), x);
  ex1 :  integrate((3*cos(2 + sqrt(3*x+4))) / (2*sqrt(3*x+4)), x);
  ex2 : changevar(ex0, u=3*x, u, x);
  ex3 : changevar(ex2, v=u+4, v, u);
  assume(w>0);
  ex4 : changevar(ex3, w=sqrt(v), w, v);
  ex5 : changevar(ex4, y=2+w, y, w);
  display2d : false;
  ex5 ;
  ex6 : ev(ex5, integrate);
  ex6 : ev(ex5, nouns);
  ex7  : subst([y=2+w],     ex6);
  ex8  : subst([w=sqrt(v)], ex7);
  ex9  : subst([v=u+4],     ex8);
  ex10 : subst([u=3*x],    ex9);
  ex1;
  ex10 - ex1;

Cheers =),
  Eduardo Ochs
  http://angg.twu.net/eev-maxima.html

On Thu, 23 Jun 2022 at 22:56, Stavros Macrakis <mac...@al...> wrote:
>
> ev(...,integrate) or ev(...,nouns)
>
> On Thu, Jun 23, 2022, 21:48 Eduardo Ochs <edu...@gm...> wrote:
>>
>> Hi list,
>>
>> I'm trying to write code that will solve some basic problems of
>> integration by change of variables "step by step"... my first example
>> starts with:
>>
>>   ex0 : 'integrate((3*cos(2 + sqrt(3*x+4))) / (2*sqrt(3*x+4)), x);
>>   ex1 :  integrate((3*cos(2 + sqrt(3*x+4))) / (2*sqrt(3*x+4)), x);
>>   ex2 : changevar(ex0, u=3*x, u, x);
>>   ex3 : changevar(ex2, v=u+4, v, u);
>>   assume(w>0);
>>   ex4 : changevar(ex3, w=sqrt(v), w, v);
>>   ex5 : changevar(ex4, y=2+w, y, w);
>>   display2d : false;
>>   ex5 ;
>>
>> but how do I make Maxima integrate ex5? Its value is:
>>
>>   'integrate(cos(y),y)
>>
>> I know how to use the quote to make Maxima _avoid solving_ an integral
>> - see ex0 and ex1 above - but how do I maka Maxima solve the integral
>> in ex5? I made several attempts using ev, simp:true, and quote-quote,
>> but none of them worked...
>>
>>   Thanks in advance!
>>     Eduardo Ochs
>>     http://angg.twu.net/eev-maxima.html
>>
>>
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