Re: [Maxima-discuss] Is there a way to expand ((1 + y )^ (1/n)) for y and n > 0?

[Stavros M. (Σ. Μ. <mac...@al...>]

powerseries((x+1)^(1/3.5),x,0);
rat: replaced 0.2857142857142857 by 2/7 = 0.2857142857142857
      (7*'sum(x^i4/beta(9/7-i4,i4+1),i4,1,inf))/9+1

taylor((x+1)^(1/3.5),x,0,3);
rat: replaced 0.2857142857142857 by 2/7 = 0.2857142857142857
       1 + (2*x)/7 - (5*x^2)/49 + (20*x^3)/343 + ...

Maxima replaces floating point numbers like 1/3.5 with rationals, in this
case 2/7, before preforming many symbolic operations.

I see no bug, and I have no idea what "Because of intrinsic decimalisation
of the term (1/n)
for any integral n during final evaluation?" means.

On Thu, Oct 18, 2018 at 11:22 PM Susmita/Rajib <bkp...@gm...>
wrote:

> Regarding my last post, n=1/4, 1/5, ..., etc., the expression /
> equation , i.e., any form, yield proper results.
> But as soon as n=1/3.5 or 1/4.3, and so on, doesn't compute.
>
> But not for n=2,3,4,... For n=2,3,4,...., the equation retains the
> same form and doesn't compute.
>
> It is just the same for powerseries function as well. I read it from
> the manual. Thanks, Mr. Willis.
>
> Is this a bug? Because of intrinsic decimalisation of the term (1/n)
> for any integral n during final evaluation?
>
>
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