Re: [Maxima-discuss] Is there a way to expand ((1 + y )^ (1/n)) for y and n > 0?

[Barton W. <wi...@un...>]

Maybe you want to set keepfloat to true:


(%i4)    block([keepfloat : true], powerseries((1 + y )^ (1/4.2),y,0));
(%o4)    0.8076923076923077*(sum(y^i4/beta(1.238095238095238-i4,i4+1),i4,1,inf))+1.0



--Barton
________________________________
From: Susmita/Rajib <bkp...@gm...>
Sent: Thursday, October 18, 2018 8:30:52 AM
To: max...@li...
Subject: Re: [Maxima-discuss] Is there a way to expand ((1 + y )^ (1/n)) for y and n > 0?

Regarding my last post, n=1/4, 1/5, ..., etc., the expression /
equation , i.e., any form, yield proper results.
But as soon as n=1/3.5 or 1/4.3, and so on, doesn't compute.

But not for n=2,3,4,... For n=2,3,4,...., the equation retains the
same form and doesn't compute.

It is just the same for powerseries function as well. I read it from
the manual. Thanks, Mr. Willis.

Is this a bug? Because of intrinsic decimalisation of the term (1/n)
for any integral n during final evaluation?


_______________________________________________
Maxima-discuss mailing list
Max...@li...
https://urldefense.proofpoint.com/v2/url?u=https-3A__lists.sourceforge.net_lists_listinfo_maxima-2Ddiscuss&d=DwICAg&c=Cu5g146wZdoqVuKpTNsYHeFX_rg6kWhlkLF8Eft-wwo&r=Ln0CjFotuA7GyhsRS-QpQA&m=hioXTyKTe8qkbBuDqOAhmhjk1AgpMKt8OHTmoQ8fWlY&s=44Zh5cHbSOubi6f4RpqGihhTeybrFDzrx8dGtQv8T2U&e=