Re: [Maxima-discuss] inverse Laplace transform

[Raymond T. <toy...@gm...>]

>>>>> "Dimiter" == Dimiter Prodanov <dim...@gm...> writes:

    Dimiter> Hi Robert,



    Dimiter> currently inverse fractional exponents are not well handled.

    Dimiter> Form like 1/s**p,  -2<p<1

specint can help with some of these inverse transfroms:

specint(1/s^p*exp(-s*t), t);

=> gamma(1-p)*t^(p-1);

Well, after you answer the questions and say t is positive and pp-1 is
negative.  I guessed it missed the part where -2<p.

It would be a decent start if ilt would call specint for things that
ilt doesn't know how to do.

--
Ray