From: James H. <j64...@gm...> - 2014-06-04 16:37:04
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Actually, I'm not sure if Maxima has a different function for the negapolygamma (of order -2 in my case), so I just assumed I could use the balanced polygamma function bfpsi in Maxima. On Wed, Jun 4, 2014 at 12:09 PM, Raymond Toy <toy...@gm...> wrote: > >>>>> "James" == James Hozier <j64...@gm...> writes: > > James> I am trying to do: limit(1 / n^2 * integrate(bfpsi(-2,x+1,16) * > (sin((2n - 1)*x) / sin(x))^3, x, 0, > James> %pi / 2), n, inf); > > > James> But I get a bunch of syntax errors, presumably because I'm > trying to put an integral inside a > James> limit. For ease of visibility, here in LaTeX typeset is what > the problem should appear as: > James> http://i.imgur.com/vjzIp5f.gif > > Several things are wrong here. 2n should be written 2*n. And based on > the image, I think bfpsi(-2,x+1,16) is not what you want. I think the > image says 1/psi(x+1)^2. > > In any case, I suspect maxima can't do the limit because maxima can't > figure out what the integral looks like. > > Ray > > > > ------------------------------------------------------------------------------ > Learn Graph Databases - Download FREE O'Reilly Book > "Graph Databases" is the definitive new guide to graph databases and their > applications. Written by three acclaimed leaders in the field, > this first edition is now available. Download your free book today! > http://p.sf.net/sfu/NeoTech > _______________________________________________ > Maxima-discuss mailing list > Max...@li... > https://lists.sourceforge.net/lists/listinfo/maxima-discuss > |