[Maxima-bugs] [ maxima-Bugs-3585415 ] integrate loops forever with simple expression

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Bugs item #3585415, was opened at 2012-11-08 07:45
Message generated for change (Settings changed) made by tomasriker
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Category: Lisp Core - Integration
Group: None
Status: Open
Resolution: None
>Priority: 7
Private: No
Submitted By: David Scherfgen (tomasriker)
Assigned to: Nobody/Anonymous (nobody)
Summary: integrate loops forever with simple expression

Initial Comment:
if you calculate this:

integrate(x^(1/3)/(x^(2/3)+1), x, 0, 8);

Maxima will compute forever and never return.
However, the indefinite integral works:

integrate(x^(1/3)/(x^(2/3)+1), x);

gives you the antiderivative:

F(x) := (3*(x^(2/3)+1))/2-(3*log(x^(2/3)+1))/2;

Now the original definite integral can be computed as F(8) - F(0).
This is OK, because F(x) doesn't change sign or shows any other notable behavior between 0 and 8.
The question is: why doesn't Maxima do this? Instead it loops forever ...

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You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=104933&aid=3585415&group_id=4933