#387 factor((x^(1/3)+1)^3) fails

[Stavros Macrakis]

factor((x^(1/3)+1)^3) fails, though factor((x^(1/3)+1)
^2) works.

The problem is presumably that in the ^2 case, the
powers of x are explicitly of the form n/3, whereas in the
^3 case, (x^(1/3))^3 => x, where the (1/3) is not
explicit.

Similarly for (x^(1/4)+1)^2.

Shouldn't factor normalize the exponents (like radcan)?

[Robert Dodier]

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Seems to work the same way in 5.9.3cvs (although I don't
fully understand what the problem is).