From: T J <tj...@gm...> - 2015-06-30 17:20:42
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Ok, sounds like I'll have to copy what those do, as I'm not planning on working with Cartesian or even curvilinear coordinates. On Tue, Jun 30, 2015 at 11:36 AM, Benjamin Root <ben...@ou...> wrote: > twinx()/twiny() I think is your best bet. It isn't a fully generic > solution, but I think it addresses most needs. > > Ben Root > > On Mon, Jun 29, 2015 at 6:00 PM, T J <tj...@gm...> wrote: > >> When I read the transformations documentation: >> >> >> http://matplotlib.org/devel/add_new_projection.html#creating-a-new-projection >> >> it seems like each projection is tied to an Axes instance. How might I >> go about plotting two different projections on the same axes? Let's just >> assume that the actual axes each projection draws is exactly same and all >> that differs between to the two is how data is mapped to axis coordinates. >> >> >> >> >> ------------------------------------------------------------------------------ >> Don't Limit Your Business. Reach for the Cloud. >> GigeNET's Cloud Solutions provide you with the tools and support that >> you need to offload your IT needs and focus on growing your business. >> Configured For All Businesses. Start Your Cloud Today. >> https://www.gigenetcloud.com/ >> _______________________________________________ >> Matplotlib-users mailing list >> Mat...@li... >> https://lists.sourceforge.net/lists/listinfo/matplotlib-users >> >> > |