Re: [Matplotlib-users] Qt4Agg backend possible bug

[V. A. S. <so...@es...>]

On 05/06/2014 15:24, Werner wrote:
> On 6/5/2014 15:10, Jorge Scandaliaris wrote:
>> Jorge Scandaliaris <jorgesmbox-ml@...> writes:
>>
>>> Hi,
>>> I just mentioned this problem with Qt4Agg and python 3.4 in another thread
>>> [1], but I decided to post it on a thread of its own, as I suspect it might
>>> be a bug in the Qt4Agg backend.
>>>
>>> I get a NameError exception (see backtrace below) when trying to use key
>>> events in matplotlib (master branch rev:
>>> e322d5f5bb024bbec44d3ba76da1bc16bf52af9c), python 3.4.1, and pyqt 4.10.
>>> Is this a bug?
>> I can confirm that using chr() instead of unichr() fixes this problem. I
>> don't know how ones handle python2 vs python3 in these cases
>>
>> diff --git a/lib/matplotlib/backends/backend_qt4.py
>> b/lib/matplotlib/backends/backend_qt4.py
>> index 70152aa..b0d8233 100644
>> --- a/lib/matplotlib/backends/backend_qt4.py
>> +++ b/lib/matplotlib/backends/backend_qt4.py
>> @@ -362,7 +362,7 @@ class FigureCanvasQT(QtGui.QWidget, FigureCanvasBase):
>>                if event_key > MAX_UNICODE:
>>                    return None
>>    
>> -            key = unichr(event_key)
>> +            key = chr(event_key)
>>                # qt delivers capitalized letters.  fix capitalization
>>                # note that capslock is ignored
>>                if 'shift' in mods:
> You would use 'six' - https://pypi.python.org/pypi/six it is used by
> many packages including wxPython.
>
> import six
>
> if six.PY3:
> 	key = chr(event_key)
>
> else:
> 	key = unichr(event_key)
>

Just for info.

I had never heard about six. Is there anything wrong using sys???:

import sys
if sys.version <  "3.0":
     key = unichr(event_key)
else:
     key = chr(event_key)

Thanks,

Armando