Re: [Matplotlib-users] Choosing optimal figure width/height automatically

[Nicolas R. <Nic...@in...>]

Would something like this suit your needs ?

import matplotlib.pyplot as plt

# Image size
width,height = 640,480

# Pixel border around image
border = 1

dpi = 72.0
figsize= (width+2*border)/float(dpi), (height+2*border)/float(dpi)
fig = plt.figure(figsize=figsize, dpi=dpi, facecolor="white")
hpixel = 1.0/(width+2*border)
vpixel = 1.0/(height+2*border)
ax = fig.add_axes([border*hpixel, border*vpixel,
                  1-2*border*hpixel, 1-2*border*vpixel])

ax.set_xlim(0, width)
ax.set_ylim(0, height)
plt.show()




Nicolas


On Oct 17, 2013, at 4:16 PM, Christoph Groth <chr...@gr...> wrote:

> Benjamin Root writes:
> 
>> I particularly like using the figaspect() function:
>> 
>> (...)
>> 
>> It isn't perfect, but for its simplicity, it gets it mostly right.
> 
> Thanks, Benjamin, for your quick reply.
> 
> Unfortunately, figaspect is only an approximate solution, as it simply
> uses the aspect ration of the image for the whole figure (with axes and
> labels).
> 
> I wonder how difficult it would be to teach matplotlib to tightly fit
> the axes around an image, and, ideally, output the figure cropped.
> 
> 
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