Re: [Matplotlib-users] Choosing optimal figure width/height automatically

[Joe K. <jof...@gm...>]

<snip>

>
> Unfortunately, figaspect is only an approximate solution, as it simply
> uses the aspect ration of the image for the whole figure (with axes and
> labels).
>
> I wonder how difficult it would be to teach matplotlib to tightly fit
> the axes around an image, and, ideally, output the figure cropped.
>

So, you're wanting the image to be displayed pixel-to-pixel, but still have
(tight) room for the axes, etc?

If so, you can use the "bbox_inches" kwarg to crop "out" and capture the
extent of the labels, etc, and just set the figure size to exactly the size
of the image.

For example:

import numpy as np
import matplotlib.pyplot as plt

dpi = 80
data = np.random.random((100, 100))

height, width = np.array(data.shape, dtype=float) / dpi

fig, ax = plt.subplots(figsize=(width, height), dpi=dpi)
ax.imshow(data, interpolation='none')
fig.savefig('test.png', bbox_inches='tight')

If show the figure (i.e. "plt.show()"), the ticklabels, etc will be outside
the figure and not shown, but they will be properly saved, regardless.

Hope that helps,
-Joe


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