Re: [Matplotlib-users] AxesGrid problem.

[Jae-Joon L. <lee...@gm...>]

This happens because, when the AxesGrid is created, gca() is set to the last
axes, which is the last colobar axes.

If you use axes_grid toolkit, you'd better not use pyplot command that works
on axes. Instead, use axes method directly.

For example, instead of  "pyplot.pcolor(..)" , use "ax.pcolor(..)".

Regards,

-JJ




On Wed, Dec 2, 2009 at 2:18 PM, Ryan Neve <rya...@gm...> wrote:

> Hello,
>
> I'm trying to use AxesGrid but I'm running into a problem:
> I can plot a single pcolor plot:
> [image: 58dFK.png]
> But when I try to use AxesGrid, my pcolor plot is ending up where I expect
> my colorbar to be.
> [image: mEbTA.png]
>
> I want to have up to 6 of these plots stacked vertically, sharing a common
> time axis and y (depth) scale.
>
> I'll try to simplify my code to show what I'm doing:
>
> # I have arrays x_grid and y_grid for time and water depth.
> # z_dim is a dictionary of arrays (one for each plot)
> # In the plot above it has two arrays.
> from matplotlib import pyplot
> nrows = len(z_dim) # Number of rows is the number of arrays
> My_figure = pyplot.figure(1,(8,8))
> my_grid = AxesGrid(My_figure, 111, #Is this always 111?
>                 nrows_ncols = (nrows,1), # Always one column
>                 axes_pad = 0.1,
>                 add_all=True,
>                 share_all=True, # They all share the same time and depth
> scales
>                 label_mode = "L",
>                 cbar_location="right",
>                 cbar_mode="each",
>                 cbar_size="7%",
>                 cbar_pad="2%",
>                 )
> for row_no,parameter in enumerate(z_dim):
>     ax = my_grid[row_no]
>     ax = pyplot.pcolor(x_grid,y_grid,z_dim[parameter])
> pyplot.draw()
> pyplot.show()
>
> I eventually want to end up with something like this matlab output (which I
> didn't generate):
> [image: jiIaK.png]
> but without the duplication of x scales.
>
> I'm new to pyplot and even after reading the documentation much of this is
> baffling.
>
> -Ryan
>
>
>
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