From: KURT P. <pet...@ms...> - 2008-03-27 15:16:54
|
And, before someone asks, "Why are you using "h" and this line: h= [seg[0]*0.000278,seg[1]*0.000278] ax.annotate(seqnum[nshape],h)", I was using this, instead, but tried to experiment with things to try to make things work right: ax.annotate(seqnum[nshape],seg) . I usually don't "give up" and post a question unless I've tried a myriad of things, and unfortunately those things sometimes show up in the example code. Regards, Kurt |