Re: [Matplotlib-users] Fwd: pylab.close() gtk error. Could be a bug (?)

[David H. <dav...@gm...>]

Hi,

What one can do is :

f =3D figure(1)
... some figure
f.clear()

f =3D figure(1)
... another figure
f.clear()

However, it is only a work around, not an actual solution...

Cheers,

David

2006/2/24, David TREMOUILLES <dav...@gm...>:
>
>    >>2006/2/24, David Huard <dav...@gm... >:
>     >>What if I want it to be non-interactive ? I want to save graphics
>     >>directly to a file from a script, without them being displayed. It'=
s
>     >>weird that in this case close() crashes the whole thing.
>
>  Yes your wright the script have to work in non interactive mode. (I was
> just trying to give an explanation to Emmanuel problem).
>  The following script should work (but it crashes like Emmanuel reported)=
:
>
>  #!/usr/bin/python
>  import matplotlib
>  import pylab
>  #Turn off interactive mode
>  matplotlib.interactive(False)
>  #plot figure 1
>  pylab.figure()
>  pylab.plot([1,2,3],[1,2,3])
>  pylab.savefig("test_pylab1.png")
>  pylab.close()
>  #plot figure 2
>  pylab.figure()
>  pylab.plot([1,2,3],[1,2,3])
>  pylab.savefig("test_pylab2.png")
>  pylab.close()
>
>  Second figure cannot be created due to the crash.
>
>  We need the help of matplotlib Gurus !
>
>  Regards,
>
>  David
>
>
>
> 2006/2/24, David Huard <dav...@gm...>:
> > What if I want it to be non-interactive ? I want to save graphics
> > directly to a file from a script, without them being displayed. It's
> > weird that in this case close() crashes the whole thing.
> >
> > David
> >
> > 2006/2/23, David TREMOUILLES < dav...@gm...>:
> > > Could that be because interactive mode was set in your previous insta=
ll
> ?
> > >  (in .matplotlibrc file)
> > >  if I try:
> > >
> > > #!/usr/bin/python
> > >  import matplotlib
> > >  import pylab
> > >  matplotlib.interactive(True)
> > >  pylab.figure()
> > >  pylab.close()
> > >
> > >  Then it works...
> > >  Hope this  could help you...
> > >
> > >  David
> > >
> > > 2006/2/23, Emmanuel Pecontal <pec...@ob...>:
> > >
> > > > Hello,
> > > >
> > > > If I run the following script on my system (SuSE 10.0, matplotlib-0=
.87
> but
> > > > same behaviour with 0.86):
> > > >
> > > > #!/usr/bin/python
> > > >
> > > > import matplotlib
> > > > import pylab
> > > >
> > > > pylab.figure()
> > > > pylab.close ()
> > > >
> > > > It crashes with the following error message:
> > > >
> > > > Traceback (most recent call last):
> > > >   File "./tmp.py", line 8, in ?
> > > >     pylab.close()
> > > >   File
> > > "/usr/lib/python2.4/site-packages/matplotlib/pylab.py",
> > > line 768, in
> > > > close
> > > >     else: _pylab_helpers.Gcf.destroy(figManager.num)
> > > >   File
> > >
> "/usr/lib/python2.4/site-packages/matplotlib/_pylab_helpers.py",
> > > line
> > > > 28, in destroy
> > > >     figManager.destroy()
> > > >   File
> > >
> "/usr/lib/python2.4/site-packages/matplotlib/backends/backend_gtk.py",
> > > > line 456, in destroy
> > > >     gtk.main_quit()
> > > > RuntimeError: called outside of a mainloop
> > > >
> > > > Does someone has an idea of the problem?
> > > > I didn't have this kind of problem with my SuSE 9.3 and
> matplotlib-0.85
> > > >
> > > > --
> > > > Emmanuel P=E9contal
> > > >
> > > > CRAL - Observatoire de Lyon
> > > > 9, Av. Charles Andre
> > > > F-69561 Saint Genis Laval Cedex
> > > >
> > > > tel (33) (0)4.78.86.83.76 - fax (33) (0)4.78.86.83.86
> > > >
> > > > email : pec...@ob...
> > > >
> > >
> > >
> >
>
>