matplotlib-users

[Matplotlib-users] legend

[Nicolas G. <hu...@ya...>]

Hello, 

I have some question on the legend.

the first is perhaps a bug:

I was trying something like:

plot([1,2,3],[2,3,4],label='toto')
legend()

I can't obtain a legend, instead I have an error
message. So perhaps I didn't understand at all the
message I obtain with: help(legend) (it's possible
with my poor english :) ) or there are a problem.

second things:
I would like to have the box create by the legend
commande behind my plot and not above because it hide
some of the point. Perhaps another solution is to put
the box bacground in "alpha mode" but I don't know how
to do this. 

I will appreciate a lot your help, thanks.


Nicolas


	

	
		
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[Matplotlib-users] legend

[Marek G. <mg...@gm...>]

Dear All,
I use hist in pylab.I have different sets of data in different colours
in one chart. In legend all rectangulars are unfortunately blue.
In plot() it is ok but not in hist().
How to receive correct colours in histogram legend?

x is nested list x[1][2][3] is an ordinary list.
for p in range(2,3):
 for c in range(0,4):
   hist(x[c][p][7],range=(0,2000),bins=20)
 title('Axis dist[m];nr '+str(p)+nams(x[3][p][7]))
 legend(['LHXGHX','>1','>3','>5'])
 figure()
Best Regards
Marek Giebułtowski

Re: [Matplotlib-users] legend

[Jae-Joon L. <lee...@gm...>]

One option is to use proxy artists.

http://matplotlib.sourceforge.net/users/legend_guide.html#using-proxy-artist

Regards,

-JJ


2010/10/26 Marek Giebułtowski <mg...@gm...>:
> Dear All,
> I use hist in pylab.I have different sets of data in different colours
> in one chart. In legend all rectangulars are unfortunately blue.
> In plot() it is ok but not in hist().
> How to receive correct colours in histogram legend?
>
> x is nested list x[1][2][3] is an ordinary list.
> for p in range(2,3):
>  for c in range(0,4):
>   hist(x[c][p][7],range=(0,2000),bins=20)
>  title('Axis dist[m];nr '+str(p)+nams(x[3][p][7]))
>  legend(['LHXGHX','>1','>3','>5'])
>  figure()
> Best Regards
> Marek Giebułtowski
>
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Re: [Matplotlib-users] legend

[John H. <jdh...@ac...>]

>>>>> "Nicolas" == Nicolas Gruel <hu...@ya...> writes:

    Nicolas> Hello, I have some question on the legend.

    Nicolas> the first is perhaps a bug:

    Nicolas> I was trying something like:

    Nicolas> plot([1,2,3],[2,3,4],label='toto') legend()

    Nicolas> I can't obtain a legend, instead I have an error
    Nicolas> message. So perhaps I didn't understand at all the
    Nicolas> message I obtain with: help(legend) (it's possible with
    Nicolas> my poor english :) ) or there are a problem.

Yep, it's a bug.  Replace the indicate line from axes.py

   loc = kwargs.gry('loc', 1)
                
with 

   loc = kwargs.get('loc', 1)
                ^^^

Note to self: run pychecker more often.

    Nicolas> second things: I would like to have the box create by the
    Nicolas> legend commande behind my plot and not above because it
    Nicolas> hide some of the point. Perhaps another solution is to
    Nicolas> put the box bacground in "alpha mode" but I don't know
    Nicolas> how to do this.

http://sourceforge.net/mailarchive/forum.php?thread_id=6039503&forum_id=33405

JDH

Re: [Matplotlib-users] legend

[Humufr <hu...@ya...>]

Hi John,

I tried:


 > Yep, it's a bug.  Replace the indicate line from
 > axes.py
 >
 >    loc = kwargs.gry('loc', 1)
 >                
 > with
 >
 >    loc = kwargs.get('loc', 1)
 >                 ^^^

That correct the problem with legend() but I have another problem and I 
think it's another bug (not sure) it's not possible to tell to 
matplotlib in this case o use the "loc" keywords more it's impossible to 
use this keywords. There are always an error message:
  File "<string>", line 3, in legend
  File "/usr/lib/python2.3/site-packages/matplotlib/axes.py", line 1502, 
in legend
    self.legend_ = Legend(self, lines, labels, loc, **kwargs)
TypeError: __init__() got multiple values for keyword argument 'loc'


example:

plot ([2,3],[4,5])
legend(('toto'),loc=2)

I tried everything: loc='upper left', loc=0,1 , loc=(0,1), loc=2 etc. 
Nothing work but if I omit the " loc=  " . It's ok and that explain 
probably why I cant do something like:

plot([1,2],[4,5],label='toto')
legend(loc='upper left')


Another strange thing I remark is:

if you are doing:

plot([1,2],[4,5])
legend(('toto'))

the text for the legend is vertical and not horizontal, that's work 
normally when we are using more than one argument.

Thank you very much for you fast answer and sorry for the second 
question I had to verify more precisely in the archival.


Nicolas

Re: [Matplotlib-users] legend

[Jochen V. <vo...@se...>]

Hello Nicolas

On Wed, Dec 01, 2004 at 09:34:51AM -0500, Humufr wrote:
> Another strange thing I remark is:
>=20
> if you are doing:
>=20
> plot([1,2],[4,5])
> legend(('toto'))
>=20
> the text for the legend is vertical and not horizontal, that's work=20
> normally when we are using more than one argument.
This happens because ('toto') is not a one-element list
but a string.  If you write

  plot([1,2],[4,5])
  legend(('toto',))

instead it works as expected.

I hope this helps,
Jochen
--=20
http://seehuhn.de/

Re: [Matplotlib-users] legend

[John H. <jdh...@ac...>]

>>>>> "Jochen" == Jochen Voss <vo...@se...> writes:

    Jochen> Hello Nicolas
    Jochen> On Wed, Dec 01, 2004 at 09:34:51AM -0500, Humufr wrote:
    >> Another strange thing I remark is:
    >> 
    >> if you are doing:
    >> 
    >> plot([1,2],[4,5]) legend(('toto'))
    >> 
    >> the text for the legend is vertical and not horizontal, that's
    >> work normally when we are using more than one argument.
    Jochen> This happens because ('toto') is not a one-element list
    Jochen> but a string.  If you write

    Jochen>   plot([1,2],[4,5]) legend(('toto',))

    Jochen> instead it works as expected.

This is such a common mistake I think we should special case string
input for the labels and make it a len(1) tuple

   if is_string_like(labels): labels = (labels, )

All opposed, say nay!

JDH

Re: [Matplotlib-users] legend

[Humufr <hu...@ya...>]

       Hi John,

I just recuperate the cvs and I saw that you correct a lot of things 
inside the legend, thanks very much.

you will hate me soon I think :) but I found one bug and onething I 
don't like too much:


1)

the bug:

I tried:

plot([1,2],[4,5],'g^',markersize=4,label='1')
errorbar([1,4],[6,7],[1,1],fmt='bh',markersize=4,label='4')

#plot([3,4],[6,7])

legend()

show()


and there are a problem with errorbar and the label and the legend. 
Different line appeard and at the end we have only the good symbols)

2)

I add the line: plot([3,4],[6,7])  only to show you that even if the 
plot command doesn't have a label the legend give a place for it. I 
think at two solution to solve this (perhaps it's already implemented 
and I didn't find...):

- by default if there are some label with the plot command the plot 
command without are not take in count to create the legend

- add something like: label=None to indicate the the user don't want 
this line in the legend.

Thanks again to have found and correct all this bug so fast, I'm very 
impressed :)

Nicolas

Re: [Matplotlib-users] legend

[John H. <jdh...@ac...>]

>>>>> "Humufr" == Humufr  <hu...@ya...> writes:


    Humufr> the bug:

    Humufr> I tried:

    Humufr> plot([1,2],[4,5],'g^',markersize=4,label='1')
    Humufr> errorbar([1,4],[6,7],[1,1],fmt='bh',markersize=4,label='4')
    Humufr> #plot([3,4],[6,7])
    Humufr> legend()
    Humufr> show()


    Humufr> and there are a problem with errorbar and the label and
    Humufr> the legend. Different line appeard and at the end we have
    Humufr> only the good symbols)

I don't consider this a bug but maybe you can convince me :-).  Legend
tries to be helpful but not omniscient.  If you have many lines and
only want to include some of them in the legend, just use the explicit
legend(lines, labels) form

    from matplotlib.matlab import *
    l1, = plot([1,2],[4,5],'g^',markersize=4)
    l2, errlines = errorbar([1,4],[6,7],[1,1],fmt='bh',markersize=4)

    plot([3,4],[6,7])

    legend((l1, l2), ('1', '4'))

    show()

Your suggestion that the legend ignore lines with empty labels appears
reasonable at first glance, but as Norbert will tell you, some people
use the fact that matplotlib legends include lines with empty labels
to their advantage when laying out legends.  

So in this case there is a way to get matplotlib to make the legend
you want, and if legend tries to get too smart about guessing what you
want it will get in the way of power users who don't what matplotlib
guessing what they are trying to do.

    Humufr> 2)

    Humufr> I add the line: plot([3,4],[6,7]) only to show you that
    Humufr> even if the plot command doesn't have a label the legend
    Humufr> give a place for it. I think at two solution to solve this
    Humufr> (perhaps it's already implemented and I didn't find...):

    Humufr> - by default if there are some label with the plot command
    Humufr> the plot command without are not take in count to create
    Humufr> the legend

    Humufr> - add something like: label=None to indicate the the user
    Humufr> don't want this line in the legend.

This could work.  Currently the default label is '', which as I said
is a perfectly legitimate label in some cases.  We could use None as a
hint to legend.  It would increase the coding burden somewhat, since
we'd always have to check for None before performing string ops on the
legend.  I'm amenable to this approach.  Anyone else have input here?

    Humufr> Thanks again to have found and correct all this bug so
    Humufr> fast, I'm very impressed :)

Thanks!
JDH

Re: [Matplotlib-users] legend

[Norbert N. <Nor...@gm...>]

Hi there,

apart from the "gry"-typo, the currect CVS-code really is in a broken state 
after my patch was applied and half-way reverted back. (The python2.2-pop 
problem)

Possible solutions:

* change "kwargs.get('xxx',def)" to "popd(kwargs,'xxx',def)" and add popd to 
the import from cbook

* change "kwargs.get('xxx',def)" to "kwargs.pop('xxx',def)" (will not work for 
Python 2.2

* change the last lines of Axes.legend according to:
         lines = flatten(lines)
+        kwargs["loc"] = loc
+        self.legend_ = Legend(self, lines, labels, **kwargs)
-        self.legend_ = Legend(self, lines, labels, loc, **kwargs)
         return self.legend_

I guess, the first solution is, what will be done in the long run.

Ciao,
Nobbi




Am Mittwoch, 1. Dezember 2004 15:34 schrieb Humufr:
> Hi John,
>
> I tried:
>  > Yep, it's a bug.  Replace the indicate line from
>  > axes.py
>  >
>  >    loc = kwargs.gry('loc', 1)
>  >
>  > with
>  >
>  >    loc = kwargs.get('loc', 1)
>  >                 ^^^
>
> That correct the problem with legend() but I have another problem and I
> think it's another bug (not sure) it's not possible to tell to
> matplotlib in this case o use the "loc" keywords more it's impossible to
> use this keywords. There are always an error message:
>   File "<string>", line 3, in legend
>   File "/usr/lib/python2.3/site-packages/matplotlib/axes.py", line 1502,
> in legend
>     self.legend_ = Legend(self, lines, labels, loc, **kwargs)
> TypeError: __init__() got multiple values for keyword argument 'loc'
>
>
> example:
>
> plot ([2,3],[4,5])
> legend(('toto'),loc=2)
>
> I tried everything: loc='upper left', loc=0,1 , loc=(0,1), loc=2 etc.
> Nothing work but if I omit the " loc=  " . It's ok and that explain
> probably why I cant do something like:
>
> plot([1,2],[4,5],label='toto')
> legend(loc='upper left')
>
>
> Another strange thing I remark is:
>
> if you are doing:
>
> plot([1,2],[4,5])
> legend(('toto'))
>
> the text for the legend is vertical and not horizontal, that's work
> normally when we are using more than one argument.
>
> Thank you very much for you fast answer and sorry for the second
> question I had to verify more precisely in the archival.
>
>
> Nicolas
>
>
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Re: [Matplotlib-users] legend

[John H. <jdh...@ac...>]

>>>>> "Norbert" == Norbert Nemec <Nor...@gm...> writes:

    Norbert> Hi there, apart from the "gry"-typo, the currect CVS-code
    Norbert> really is in a broken state after my patch was applied
    Norbert> and half-way reverted back. (The python2.2-pop problem)

    Norbert> Possible solutions:

    Norbert> * change "kwargs.get('xxx',def)" to
    Norbert> "popd(kwargs,'xxx',def)" and add popd to the import from
    Norbert> cbook

Here is what I committed to CVS earlier today in axes.Axes.legend

        if len(args)==0:
            labels = [line.get_label() for line in self.lines]
            lines = self.lines
            loc = popd(kwargs, 'loc', 1)

and more like it.  I think this works...

JDH